<script type="text/javascript">
function getXY(){
window.status = "(" + window.event.x + "," + window.event.y + ")";

}

document.onmousemove = getXY;
</script>
这是一段随鼠标移动在状态栏显示坐标变换的代码
如果我想实现当鼠标移动过某一段坐标后弹出对话框，应该怎样写代码
急盼高手回复

<script type="text/javascript">
function getXY(x1,x2,y1,y2){
window.status = "(" + window.event.x + "," + window.event.y + ")";
if(event.x<x2&&event.x>x1&&event.y<y2&&event.x>y1) alert("弹出窗口");

}

document.onmousemove = getXY;
</script>
还要改动什么?

<script language="JavaScript">

function getXY(){
var x1=252;
var x2=392;
var y1=100;
var y2=288;
window.status = "(" + window.event.x + "," + window.event.y + ")";
if(event.x<x2&&event.x>x1&&event.y<y2&&event.x>y1) {
alert("弹出窗口");
}

}

document.onmousemove = getXY;
</script>
终于完成了，原来是没定义变量．
非常感谢２楼给予的提示．