程序代码：

#include <stdio.h>

int main()
{
    const int ch1[10]={0XD2BB,0XB6FE,0XC8FD,0XCBC4,0XCEE5,
                       0XC1F9,0XC6DF,0XB0CB,0XBEC5,0XCAAE};

    char ch2[3]={'\0','\0','\0'};
    for(int k=0;k<10;k++)
    {
        ch2[0]=ch1[k]>>8;
        ch2[1]=ch1[k];
        ch2[2]='\0';
        printf("%s",ch2);
    }
    printf("\n");
    return 0;
}

程序代码：

#include<stdio.h>
#include<string.h>

char * chinese_number(int a, char * strcn)
{
    char * b = "个十百千万亿";
    char * c = "零一二三四五六七八九";
  
    int s[16] = {0}, n, i, t;
    //另s[]保存了输入数字的每位元素
    //例：输入a=12345 则s[0..4]分别为5,4,3,2,1
    i=0;
    memset(s,0,sizeof(s));
    while(a)
    {
        s[i]=a % 10;
        a=a/10;
        i++;
    }
    n=i;
    i=0;
    while(1)
    {
         if(n==-1) break;
        n--;
        if(s[n]!=0)
        {
            if(s[n+1] == 0)
            {
                strcn[i++] = c[0];
                strcn[i++] = c[1];
            }
            strcn[i++] = c[s[n] * 2];
            strcn[i++] = c[s[n] * 2 + 1];
            if(t = n % 4)
            {
                strcn[i++] = b[t * 2];
                strcn[i++] = b[t * 2 + 1];
            }
        }
        if(n!=0)
        {
            if(n % 8 == 0)
            {
                strcn[i++] = b[10];
                strcn[i++] = b[11];
            }
            else if(n % 4 == 0)
            {
                strcn[i++] = b[8];
                strcn[i++] = b[9];
            }
        }
    }
    strcn[i] = '\0';
    if(i==0)
    {
        strcn[0] = c[0];
        strcn[1] = c[1];
        strcn[2] = '\0';
    }
    return strcn;
}


int main()
{
    char s[128];
    int a;
    printf("Try to input a number : ");
    scanf("%d", &a);
    puts(chinese_number(a, s));
    return 0;
}