题目：输入某年某月某日，判断这一天是这一年的第几天？


#include"stdio.h"
main()
{
int day,month,year,sum,leap;
printf("input year,month,day\n");
scanf("%d,%d,%d",&year,&month,&day);
switch(month)
{
　case 1:sum=0;break;
　case 2:sum=31;break;
　case 3:sum=59;break;
　case 4:sum=90;break;
　case 5:sum=120;break;
　case 6:sum=151;break;
　case 7:sum=181;break;
　case 8:sum=212;break;
　case 9:sum=243;break;
　case 10:sum=273;break;
　case 11:sum=304;break;
　case 12:sum=334;break;
　default:printf("data error");break;
}
sum=sum+day; 　
　if(year%400==0||(year%4==0&&year%100!=0))
　　leap=1;
　else
　　leap=0;
if(leap==1&&month>2)
sum++;
printf("It is the %dth day.",sum);}


为什么我运行的时候说出现错误呢，哪位高手帮我改改啊

我重编了下可以运行了，呵呵

#include"stdio.h"
main()
{
    int day,month,year,sum,leap;
    printf("input year,month,day\n");
    sum=0;
    scanf("%d,%d,%d",&year,&month,&day);
    switch(month)
     {
         case 1:  sum=0; break;
         case 2:  sum=31;break;
         case 3:  sum=59; break;
         case 4:  sum=90; break;
         case 5:  sum=120; break;
        case 6:  sum=151; break;
        case 7:  sum=181;break;
        case 8:  sum=212;break;
           case 9:  sum=243;break;
           case 10: sum=273;break;
           case 11: sum=304;break;
           case 12: sum=334;break;
        default : printf("data error"); break;
     }
   sum=sum+day;
    if(year%400==0||(year%4==0&&year%100!=0))   
       
      leap=1;
      else leap=0;
      if(leap==1&&month>=2)
      sum++;
      printf("it is the %dth day.",sum);
}

呵呵，知道啊