题目：输入某年某月某日，判断这一天是这一年的第几天？


#include"stdio.h"
main()
{
int day,month,year,sum,leap;
printf("input year,month,day\n");
scanf("%d,%d,%d",&year,&month,&day);
switch(month)
{
　case 1:sum=0;break;
　case 2:sum=31;break;
　case 3:sum=59;break;
　case 4:sum=90;break;
　case 5:sum=120;break;
　case 6:sum=151;break;
　case 7:sum=181;break;
　case 8:sum=212;break;
　case 9:sum=243;break;
　case 10:sum=273;break;
　case 11:sum=304;break;
　case 12:sum=334;break;
　default:printf("data error");break;
}
sum=sum+day; 　
　if(year%400==0||(year%4==0&&year%100!=0))
　　leap=1;
　else
　　leap=0;
if(leap==1&&month>2)
sum++;
printf("It is the %dth day.",sum);}


为什么我运行的时候说出现错误呢，哪位高手帮我改改啊

scanf("%d,%d,%d",&year,&month,&day);
你的输入语句是这样，所以你输入数据应该是XXXX,XX,XX而不是XXXX XX XX(你应该是输入时没加逗号，所以没有结果)

编译时就通不过了，不是scanf的问题

经过我仔细研究发现，这代码你肯定不是自己写的，是抄的，罚你回去自己敲一遍就能运了，
不能得话来找我！

sum没有置零啊

用置零么?

给你调好了 ，学了那么久的c了，这样的问题我还是头一次遇见
下面的代码自己试试啊，是你的书写形式没有搞好啊

#include<stdio.h>
main()
{
    int day,month,year,sum,leap;
    
    scanf("%d,%d,%d",&year,&month,&day);
    sum=0;
    printf("input year,month,day\n");
    switch(month)
    {
        case 1:    sum=0;break;
        case 2: sum=31;break;
        case 3:
        sum=59;break;
        case 4:
        sum=90;break;
        case 5:
        sum=120;break;
        case 6:
        sum=151;break;
        case 7:
        sum=181;break;
        case 8:
        sum=212;break;
        case 9:
        sum=243;break;
        case 10:
        sum=273;break;
        case 11:
        sum=304;break;
        case 12:
        sum=334;break;
        default:
        printf("data error");break;
    }     
    sum=sum+day;
        if(year%400==0||(year%4==0&&year%100!=0))
    leap=1;
    else
    leap=0;
    if(leap==1&&month>2)
     sum++;
    printf("It is the %dth day.",sum);
}

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[])
{
    int day, month, year, sum = 0, leap;

    printf("input year,month,day\n");
    scanf("%d,%d,%d", &year, &month, &day);
    switch (month)
    {
    case 1:sum = 0; break;
    case 2:sum = 31; break;
    case 3:sum = 59; break;
    case 4:sum = 90; break;
    case 5:sum = 120; break;
    case 6:sum = 151; break;
    case 7:sum = 181; break;
    case 8:sum = 212; break;
    case 9:sum = 243; break;
    case 10:sum = 273; break;
    case 11:sum = 304; break;
    case 12:sum = 334; break;
    default:printf("data error"); exit(1);
    }
    sum = sum + day;
    if((year % 400 == 0) || (year % 4 == 0 && year % 100 != 0))
        leap = 1;
    else
        leap = 0;
    if(leap == 1 && month > 2)
        sum++;
    printf("It is the %dth day.\n", sum);
    
    return 0;
}

[[it] 本帖最后由 printc 于 2009-7-31 17:47 编辑 [/it]]

我重编了下可以运行了，呵呵

#include"stdio.h"
main()
{
    int day,month,year,sum,leap;
    printf("input year,month,day\n");
    sum=0;
    scanf("%d,%d,%d",&year,&month,&day);
    switch(month)
     {
         case 1:  sum=0; break;
         case 2:  sum=31;break;
         case 3:  sum=59; break;
         case 4:  sum=90; break;
         case 5:  sum=120; break;
        case 6:  sum=151; break;
        case 7:  sum=181;break;
        case 8:  sum=212;break;
           case 9:  sum=243;break;
           case 10: sum=273;break;
           case 11: sum=304;break;
           case 12: sum=334;break;
        default : printf("data error"); break;
     }
   sum=sum+day;
    if(year%400==0||(year%4==0&&year%100!=0))   
       
      leap=1;
      else leap=0;
      if(leap==1&&month>=2)
      sum++;
      printf("it is the %dth day.",sum);
}

好熟悉啊 要自己做

#include"stdio.h"
main()
{
    int day,month,year,sum,leap;
    printf("input year,month,day\n");
    sum=0;
    scanf("%d,%d,%d",&year,&month,&day);
    switch(month)
     {
         case 1:  sum=0; break;
         case 2:  sum=31;break;
         case 3:  sum=59; break;
         case 4:  sum=90; break;
         case 5:  sum=120; break;
        case 6:  sum=151; break;
        case 7:  sum=181;break;
        case 8:  sum=212;break;
           case 9:  sum=243;break;
           case 10: sum=273;break;
           case 11: sum=304;break;
           case 12: sum=334;break;
        default : printf("data error"); break;
     }
   sum=sum+day;
    if(year%400==0||(year%4==0&&year%100!=0))   
        
      leap=1;
      else leap=0;
      if(leap==1&&month>=2)
      sum++;
      printf("it is the %dth day.",sum);
}