用getchar()编写程序,从键盘读入字符,知道遇上#停止,计算a, b, c出现次数
#include "stdio.h"

int main(void)
{
    int   a ,b ,c ;
    int   d;
    a = b = c = 0;
    while((d = getchar()) != '#'){
        if (d == 'a')
            ++a;
        if (d == 'b')
            ++b;
        if (d =='c')
            ++c;
      putchar(d);
      printf("\na is printed  %d, b is printed  %d, c is printf  %d.\n",a, b, c);
       
     }
    return 0;
}
如果输入d,就显示
d
a is printed 0, b is printed 0, c is printed 0.

a is printed 0, b is printed 0, c is printed 0.
不解中

不好意思啊,貌似还是不行,输出还是2次

他为什么会显示??
要怎么做才能不显示呢??

#include "stdio.h"

int main(void)
{
    char    a;
    printf("input a letter:  \n");
    scanf("%c\n",&a);
    printf("%c is printed.\n",a);
    return 0;
}
这个输出很有问题啊,输入c的时候没显示,再输入另一个字符输出c,搞不懂了