用getchar()编写程序,从键盘读入字符,知道遇上#停止,计算a, b, c出现次数
#include "stdio.h"

int main(void)
{
    int   a ,b ,c ;
    int   d;
    a = b = c = 0;
    while((d = getchar()) != '#'){
        if (d == 'a')
            ++a;
        if (d == 'b')
            ++b;
        if (d =='c')
            ++c;
      putchar(d);
      printf("\na is printed  %d, b is printed  %d, c is printf  %d.\n",a, b, c);
       
     }
    return 0;
}
如果输入d,就显示
d
a is printed 0, b is printed 0, c is printed 0.

a is printed 0, b is printed 0, c is printed 0.
不解中

把printf("\na is printed  %d, b is printed  %d, c is printf  %d.\n",a, b, c); 放在while語句外面就可以了~

定义 d的数据类型为  char,

就可以了

這樣是可以不過有幾個字符就輸出幾個了~~  那樣屏幕滿了~~

是的，前面你不是说了把printf()放在while语句的后面，我只是省略了

那我錯了~  sorry...

d
a is printed 0, b is printed 0, c is printed 0.
这下面一行是你敲回车时存在字符缓冲区的回车符没有显示出来。
a is printed 0, b is printed 0, c is printed 0.

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不好意思啊,貌似还是不行,输出还是2次

他为什么会显示??
要怎么做才能不显示呢??