还有一个问题
int *p = new int(0);
和
int *pt = new int[5];
中
两个 new 是否是同一种东西

new is just an operator, how it will be used, dependent on that how you used it.

the first
int *p = new int(0); 4 Byte allocation, and initialized with value 0; p will be assigned the address, under this address will this value 0 saved.

the second
int * pt = new int [5]; dynamically allocation for an integer array with 5 integer. After allocation, pt get the first address of this allocation. because every integer need 4 Byte, so 5 integer need 20 Byte, that mean the allocation is 20 Byte allocation. and After the allocation the first address will be assigned to pt.

穆扬,

don't make it confuse.

int * p = new int[5]; you should know p get an address, just an address, for example 3000, but p is not from type int *, p here is an point to an array.

The important is that you can image what in really stand. That mean, you should view the physicalishe image.

穆扬,

C++ there is just one C++ not two, or more. Why you will think, there is not only one C++? I think you need learn it.

世界上究竟有没有不懂c的c++的“高手” I think, no , there is no C++ master who don't know C, because C++ include C. Maybe C++ Master can not write good code in C. And there is really too more C Master who don't know C++ any more.

穆扬,

a pointer will get an address, and something more, a pointer has still a type. As programmer, you should see that, and more things you should get is, you should get an image what really in physical is. That is the difference between an normal programmer and a master.

A master can image, what happend after a statement, not just datetype, but also what in physicalisch level happend. When you can do that, then you can write the code, what you want, and safe and efficient.

自己的new malloc在堆