程序代码：

assume cs:code,ds:data,es:table

data segment

    db    '1975','1976','1977','1978','1979','1980','1981','1982','1983'
    db    '1984','1985','1986','1987','1988','1989','1990','1991','1992'
    db    '1993','1994','1995'

    dd    16,22,382,1356,2390,8000,16000,24486,50065,97497,140417,197514
    dd    345980,590827,803530,1183000,1843000,2759000,3753000,4649000,5937000

    dw    3,7,9,13,28,38,130,220,476,778,1001,1442,2258,2793,4037,5635,8226
    dw    11542,14430,15257,17800

data ends

table segment

    db    21 dup ('yaar sumn ne ?? ')

table ends

code segment

start:

    mov        ax, data
    mov        ds, ax

    mov        ax, table
    mov        es, ax

    mov        bx, 0
    mov        si, 0
    mov        cx, 21        ;初始外循环次数

start0:

    mov        cx, 8
    mov        ax, ds:[bx]
    mov        word ptr es:[bx], ax
    add        bx, 2
    mov        ax, ds:[bx]
    mov        es:[bx], ax
    add        bx, 2
    mov        word ptr es:[bx], 20h                ;year and space

    add        bx, 1
    mov        ax, ds:[bx]
    mov            es:[bx], ax
    add        bx, 2
    mov         dx, ds:[bx]
    mov         es:[bx], dx
    add        bx, 2
    mov        word ptr es:[bx], 20h            ；earn  and space   


    add         bx, 1
    mov        si, ds:[bx]
    mov        es:[bx], si
    add        bx, 2
    mov        word ptr es:[bx], 20h        ;member and space   20h = ' '                             //这句报错。open parenthesis or bracket   想不明白 到底嘛意思             

    div        si                ;everyone 's money

    add        bx, 1
    mov        es:[bx], ax

    add        bx, 2
    add        bx, 1
   


loop start0

    mov        ax, 4c00h
    int        21h

end start