好是好 可是显示的格式没有达到题目的要求！

是吗,我没编译器,不好意思啊

#include<stdio.h>
main()
{ int i,n,sum;
scanf("%d",&n);/*ÊäÈëÊý*/
for(i=1;i<=10;i++)
{
printf("%2d *%2d=%2d",n,i,n*i);
printf("\t%2d *%2d=%2d\n",n,i,n*i);

} }

哇，谢谢各位啦！13楼的大哥 好棒哦！

#include <stdio.h>
#include <stdlib.h>
int i=1;
unsigned int num,j=1;
int main (void){
if(i){
printf ("insert a number:");
scanf ("%u",&num);
}
i=0;
if (num>=j){
printf ("%u*%d=%.2u ",num,j,num*j);
if(j%2==0)
printf("\n");
j++;
main();
}
exit(0);
}

你输出的时候用printf("%d*%d=%d",i,j,i*j);

#include <stdio.h>

int main(void)
{
unsigned int n;
unsigned char i = 0;
unsigned int str[11];


printf("please input a number:\n");
scanf("%d", &n);

for(i=1; i<6; i++)
{
str[2*i-1] = n*(2*i-1);
str[2*i] = n*2*i;
printf("%d*%d=%d %d*%d=%d\n", 2*i-1, n, str[2*i-1], 2*i, n, str[2*i] );
}
return 1;
}

#include "Stdio.h"

int main()
{
int i,num;
printf("输入一个数:");
scanf("%d",&num);
for(i=1;i<=10;i++)
{
printf("%d * %d=%-7ld",num,i,num*i);
if(i%2==0)
{
printf("\n");
}
}
return(0);
}

看了上面的代码都少了一句“press any key to contonue!”
在此补上！
#include<stdio.h>
main()
{
int i,m=1;
char t;
clrscr();
l:printf("please input a number:\n");
scanf("%d",&i);
for(m=1;m<11;m++)
{
printf("%d*%d=%d",i,m,i*m);
printf(" ");
if(m%2==0)
printf("\n");
}
printf("press any key to continue!\n");
printf("press q to exit!\n");
t=getch();
if(t!='q')
{goto l; }
exit(0);
}

#include <stdio.h>

int main()
{
int i;
long num, total;
printf ("请输入一个整数 : ");
scanf ("%ld", &num);
for (i=1; i<=10; i++ )
{
printf ("%ld * %d = %ld ", num, i, total=num*i);
if ( (i % 2) == 0 )
{
printf("\n");
}
}
getch ();
return 0;
}