对称完整版：
#include<stdio.h>
int fun(int a[][4],int n);
int main()
{
     int a[4][4];
     int i,j;
     for (i=0;i<4;i++)
         for (j=0;j<4;j++)
             scanf("%d",&a[i][j]);
    fun(a,1);
    fun(a,2);
    return 0;
 }
int fun(int a[][4],int n)
{
    int i,j;
    static t=0;
     for (i=0;i<4;i++)
         for (j=0;j<4;j++)
             if (a[i][j]!=a[i][3-j]&&n==1)
             {
                 printf("不是左右对称\n");
                 return 0;
             }
             else if (a[i][j]!=a[3-i][j]&&n==2)
             {
                 printf("不是上下对称\n");
                 printf("不是中心对称\n");
                 return 0;
             }
    if (n==1)
    {
        printf("是左右对称\n");
        t++;
     }
     if (n==2)
     {
         printf("是上下对称\n");
         t++;
     }
    if (t==2)
        printf("是中心对称\n");
    return 0;
}

或者不用函数也行

#include<stdio.h>
int main()
{
     int a[4][4],i,j,t;
     for (i=0;i<4;i++)
         for (j=0;j<4;j++)
             scanf("%d",&a[i][j]);
     for (i=t=0;i<4;i++)
         for (j=0;j<4;j++)
         {
             if (a[i][j]!=a[i][3-j]&&(t==0||t==5||t==3))t=t+1;
             if (a[i][j]!=a[3-i][j]&&(t==0||t==4||t==3))t=t+2;
             if (a[i][j]!=a[3-i][3-j]&&(t==0||t==1||t==2))t=t+3;
             if (t==6)i=j=4;
        }
    switch (t)
    {
        case 6:printf("不对称\n");break;
        case 5:printf("左右对称\n");break;
        case 4:printf("上下对称\n");break;
        case 3:
        case 2:
        case 1:printf("中心对称\n");break;
        case 0:printf("全面对称\n");break;
    }
 }

[此贴子已经被作者于2016-11-9 05:54编辑过]

谢谢