值得学习

哦，呵呵，我懂了，原来其实 i < 6, j<=32 就行了。谢谢楼上提醒啊！

#include <stdio.h>
#include <string.h>
#include <stdlib.h>
#include <math.h>

#define LEN 6                  //数列长度
#define COUNT 160        //范围

int ary[LEN], cnt = 0;
int *a = NULL;

int judge(int m)
{
    int i;
    for(i=2; i<=sqrt(m);i++)
        if(m%i==0)
            break;
    if(i>sqrt(m))
        return 1;
    else
        return 0;
}
void GetNext(int s, int n, int d)
{
    int i;
    if (n == LEN)
    {
        for (i = 0; i < LEN; i ++)
        {
            printf("%d ", ary[i]);
        }
        printf("\n");
        return;
    }        
    for (i = s; i < cnt; i ++)
    {
        if (a[i]-ary[0] == n*d)
        {
            ary[n++] = a[i];
            GetNext(i+1, n, d);
            return;
        }
    }
}

void GetQueue(void)
{
    int i, j, d;
    for (i = 0; i < cnt; i ++)
    {
        for (j = i+1; j < cnt; j ++)
        {
            d = a[j] - a[i];
            ary[0] = a[i];
            ary[1] = a[j];
            GetNext(j, 2, d);
        }
    }
}

int main(void)
{
    int i;
    memset(ary, 0, sizeof(ary));
    for (i = 2; i < COUNT; i ++)
    {
        if (judge(i))
        {
            a = realloc(a,sizeof(int)*(++cnt));
            a[cnt-1] = i;
        }
    }
    for (i = 0 ; i < cnt; i ++)
    {
        printf("%d ", a[i]);
    }
    printf("\n");
    GetQueue();

    free(a);
}

貌似复杂了点。。。。。。。。。。

#include <stdio.h>
main()
{int i, j, m=5, n,  t=0, half, xx[160];



while(m<160)

{half=m/2;
    for(i=2;i<=half;i++)
    if(m%i==0)
    break;
if(i>half)
{
    xx[t]=m;
   t++;

}
    m++;
    }




for(i=0;i<t-5;i++)
    for(j=i+1;j<t;j++)
{n=xx[j]-xx[i];
if(xx[j+4]-xx[i]!=5*n)
break;

else if (xx[j+3]-xx[i]!=4*n)
break;

else if(xx[j+2]-xx[i]!=3*n)
break;

else if(xx[j+1]-xx[i]!=2*n)
break;/**/

else
  printf("%d %d %d %d %d %d " ,xx[i],xx[i+1],xx[i+2],xx[i+3],xx[i+4],xx[i+5]);

    }
    if(i>=t-5)
        printf("没有满足条件的数\n");


}  运行结果好像是没有

请问那个 for(i=0;i<25;i++)
        for(j=1;j<=32;j++)
  if(sushu(f[i]+j)==1 && sushu(f[i]+j*2)==1 && sushu(f[i]+j*3)==1 &&sushu(f[i]+j*4)==1 && sushu(f[i]+j*5)==1)

里的for(i=0;i<25;i++) 的25是怎么来的？