水一个


[CODE]#include <stdio.h>
int main()
{
int n = 1024;
char bArray[32];
for(int i=0;i<32;++i) bArray[i]= '\0';
_asm //是编译器不同用法不同
{
mov eax,n
lea ebx,bArray
mov ecx,32
rl:
shr eax,01
jnc d
mov dl,1
add dl,48
mov [ebx+ecx-1],dl
dec ecx
jne rl
jmp ou
d:
mov [ebx+ecx-1],48
dec ecx
jne rl
ou:
}
bool flag = false;
for(int i = 0;i<32;++i)
{
if ( bArray[i] != '0' ) flag = true;
if ( flag ) putchar(bArray[i]);
}
return 0;
}[/CODE]

在C中嵌入汇编

/*---------------------------------------------------------------------------
File name: 二进制转换.c
Author: HJin (email: fish_sea_bird [at] yahoo [dot] com )
Created on: 8/24/2007 01:42:24
Environment: Windows XP Professional SP2 English +
Visual Studio 2005 v8.0.50727.762

Modification history:
===========================================================================

Problem statement:
---------------------------------------------------------------------------
http://bbs.bc-cn.net/viewthread.php?tid=164607

在C语言中怎么把一个数转换成二进制然后输出呢？
比如：
int a=12；
怎么把他以二进制的形式1100输出呢？

Sample output:
---------------------------------------------------------------------------

Please enter an integer:
0
0
There are 1 binary bits.
0

Please enter an integer:
1
1
There are 1 binary bits.
1

Please enter an integer:
12
1100
There are 4 binary bits.
1100

Please enter an integer:
31
11111
There are 5 binary bits.
11111

Please enter an integer:
2147483647
1111111111111111111111111111111
There are 31 binary bits.
1111111111111111111111111111111

Please enter an integer:
-1
11111111111111111111111111111111
There are 32 binary bits.
11111111111111111111111111111111

Please enter an integer:
-2
11111111111111111111111111111110
There are 32 binary bits.
11111111111111111111111111111110

Please enter an integer:
-2147483647
10000000000000000000000000000001
There are 32 binary bits.
10000000000000000000000000000001

Please enter an integer:
-2147483648
10000000000000000000000000000000
There are 32 binary bits.
10000000000000000000000000000000

Please enter an integer:

*/

#include <stdio.h>
#include <stdlib.h>

int main()
{
int n;
int numBits;
int t;
int i;
char s[50];

while(1)
{
puts("\nPlease enter an integer: ");
scanf("%d", &n);

// Option 1
// itoa --- note that
// itoa is NOT a standard C function.
itoa(n, s, 2);
puts(s);

// Option 2:
if(n>=0)
{
numBits=0;
t=n;
do
{
++numBits;
t>>=1;
}
while(t);
}
else
{
numBits=32;
}
printf("There are %d binary bits.\n", numBits);

for(i=numBits-1; i>=0; --i)
{
printf("%d", (n>>i)&1);
}
printf("\n");
}

return 0;
}

#include <stdio.h>
void Foo(int a,int b)
{
if(a||b)
{
Foo(a>>1,b-1);
printf("%d",a&0x1);
}
}
int main()
{
int a;
while(scanf("%d",&a)==1)
{
printf("\n");
Foo(a,8);
printf("\n");
}
return 0;
}

if(a||b)
==>if(a&&b)

nice recursion algorihtm.

I did a few modifications to your algorithm:

=================================
#include <stdio.h>
void Foo(int a, int b)
{
if (a && b)
{
Foo(a >> 1, b - 1);
printf("%d", a& 0x1);
}
}

int main()
{
int a;
while (scanf("%d", &a) == 1)
{
if(a==0)
{
printf("0\n\n");
continue;
}
Foo(a, 32);
printf("\n\n");
}
return 0;
}

根本就不能用。。。。。

还有辗转除余输出，就像你自己算一样

回复18楼的。能详细说下怎么不能用的