*
   * A
  * A *
 * A * A
* A * A *
 这样循环下去，，有人会吗

#include <stdio.h>
int main()
{
    int i,layers,blanks;
    printf("输入层数：");
    scanf("%d",&layers);
    for(i=0;i<layers;i++)
    {
        for(blanks=layers-i-1;blanks>=0;blanks--)
            printf(" ");
        for(blanks=0;blanks<i*2+1;blanks++)
        {
            switch(blanks%4)
            {
            case 0:printf("*");break;
            case 2:printf("A");break;
            default:printf(" ");break;
            }
        }
        printf("\n");
    }
    return 0;
}

无聊当小练笔~

#include<stdio.h>
#define N 10
int main()
{
    int i=0;
    int j=0;

    for (i=0;i<N;i++,printf("\n"))
    {
        for (j=-N+i;j<i+1;j++)
        {
            if (j<0)
                printf("%c",' ');
            else
               if (j%2)
                   printf("* ");
               else
                   printf("A ");
        }

    }

    return 0;

}

#include <stdio.h>
main()
{
    char *s="* A * A *";
    int i, n=5;
    for (i=0; i<n; i++)
        printf("%*.*s\n", n+i, i*2+1, s);
}

#include<stdio.h>
#define N 5
main()
{
    int i = 0, j = 0, t = 0;
    char ch[4] = {'*', ' ', 'A', ' '};
   
    for(i = 1; i <= N; i++, printf("\n"))
    {
        t = N -i;
        while(t--)
        {
            putchar(' ');
        }
        
        for(j = 0; j < 2*i-1; j++)
        {
            printf("%c", ch[j%4]);
        }
    }
   
    return 0;
}

多谢各位

楼主写反了。

#include <stdio.h>
#define SUM ('*' + 'A')
#define MAX 30
int main(void)
{
    int i = 0, j = 0;
    for( i = 0, j = -1; i < MAX; ++i, j = -1 ) {
        while( j++ < i )
            printf("%c ", SUM - (0 == ( 1 & j) ? 'A' : '*'));
        putchar('\n');
    }
    return 0;
}

两个循环，第二个循环的时候奇数输出*偶数输出A