#include<stdio.h>

int main()
{   
    int a[4][5]=
    {10,20,30,40,50,
    11,21,31,41,51,
    12,22,32,42,52,
    13,23,33,43,53};
    int *p;
    for(p=a[0];p<a[0]+20;p++)
    {
        printf("%d",*p);
    }
    return 0;
}
main.obj : error LNK2001: unresolved external symbol _average
Debug/main.exe : fatal error LNK1120: 1 unresolved externals
Error executing link.exe.

main.exe - 2 error(s), 0 warning(s)
提示这些东西，搞不懂哪个地方错了，我是新手啊 求大神指点一二，跪求！
能不能用两个指针来输出 求大神教我啊！

#include<stdio.h>

 int main()
 {   
     int i;
     int a[]=
     {10,20,30,40,50,
     11,21,31,41,51,
     12,22,32,42,52,
     13,23,33,43,53};
     int b[4][5]=
     {10,20,30,40,50,
     11,21,31,41,51,
     12,22,32,42,52,
     13,23,33,43,53};
     for(i = 0;i < 20; i++)
     {
         printf("  %d  ", *(a + i));
     }
     printf("\n\n\n");
     for(i = 0;i < 20; i++)
     {
         printf("  %d  ", **(b + i));
     }
     printf("\n\n\n");
     int *p;
     for(p = &b[0][0];p < &b[0][0] + 20; p++)
     {
         printf("  %d  ", *p);
     }
     
      return 0;
      
 }

//把这个输出来，你马上就明白了

#include<stdio.h>

int main()
{   
    int a[4][5]=
    
    {10,20,30,40,50,
    
    11,21,31,41,51,
    
    12,22,32,42,52,
    
    13,23,33,43,53};
    
    int(*p)[5];//定义指向二维数组的真
    
    p = a;
    
    int i,j;
   
   for(i = 0; i < 4; i++)
   {
       for(j = 0; j < 5; j++)
       
            printf("%d ",a[i][j]); 
           printf("%d ",*(*p + i) + j);//如果用指针表示的话是这样 ，与上面那个printf等效 
             putchar('\n');  
        
   }
    
    return 0;
    
}

你这个是二维数组，所以定义指针的时候要定义一个指向二维数组的指针

好的非常感谢大神给我解答，现在我明白了😊