#include <stdio.h>
#include <stdlib.h>
#define len 10
int main(){
    int array[len]={1,2,3,4,5,6,7,8,9,10},*ptr,i;
 
    ptr=array;
    for(i=0;i<len;i++)
    scanf("%d",ptr+i);

    for(i=0;i<len;i++){
      if(i%2==0){
        printf("*%d",*(ptr+i));}
    else                                                                                                                                                                                                                                                                                                                                                                           
      printf("\n");
}
    system("PAUSE");
    return 0;
 }
 题目：指针实现：输入一个10个元素数组，输出数组奇数位置的元素。

没问题啊,  array[len]={0} 所有数字都置0就好了

[此贴子已经被作者于2016-12-1 17:13编辑过]

#include <stdio.h>
#include <stdlib.h>
#define len 10
int main(){
    int array[len]={1,2,3,4,5,6,7,8,9,10},*ptr,i;
 
    ptr=array;
    for(i=0;i<len;i++)
        scanf("%d",ptr+i);

    for(i=0;i<len;i+=2)//如果是下标为奇数，则改成i=1
        printf("%d  ",*(ptr+i));
  
}
    system("PAUSE");
    return 0;
 }

[此贴子已经被作者于2016-12-1 18:41编辑过]

int array[len]={0}就行了