#include <stdio.h>
#include <stdlib.h>
int main (void)
{
    int year = 0;
    int month = 0;
    int day = 0;
    scanf ("%d\n",&year);
    scanf ("%d\n",&month);
    if ( month >12 || month <1 )
    {
        printf ("this month is nothingness ,input again !");
      if (day >31 || day <1)
    printf ("your error !");
    }
    if (day >31 || day <1)
    {
        day = 32;
    switch (day)
    {
    case 1 : case 21 : case 31:
        printf ("today is %dst %d %d",day,month,year);
        break;
    case 2: case 22:
        printf("today is %dnd %d %d",day,month,year);
        break;
    case 3: case 23:
        printf ("today is %drd %d %d",day,month,year);
        break;
    case 32:
        printf ("your error !");
        break;
    default :
        printf ("today is %dth %d %d",day,month,year);
        break;
    }
    }
    system ("pause");
    return 0;
}
求各位大大帮我看看我这段写的还有问题。还有求各位大大指点一下怎么在最后的输出中将数字月份的输出编程英文月份的描述，需要怎么操作？

大概是这个意思吧

#include <stdio.h>
#include <stdlib.h>
int main (void)
{
    int year = 0;
    int month = 0;
    int day = 0;
    scanf ("%d",&year);///
    scanf ("%d",&month);//
    if ( month >12 || month <1 )
    {
        printf ("this month is nothingness ,input again !");
       
    }
    else{
       
        scanf ("%d",&day);
        if (day >31 || day <1)
            printf ("your day error !");
        else
        {
           
            printf ("today is %dst %d %d\n",day,month,year);
           
           
        }
   
}

 system ("pause");
return 0;
}

我是希望您能帮我看一下我写的代码是不是有问题及能不能指点我一下我后面问的那个问题，谢谢，希望您能指导我一下

int main（void）是什么意思
主函数不是int main（）吗
运行你这个程序需要输入3个数，但我就看见俩个，第三个在那
swich后的（）是选项，如果是case1，（）的值里就是1。