[local]1[/local]

main()
{
    char *password[]=
    {"Cat","Mouse","Dog","Sugar","Water","Meat","Steel"};
    char mima[100];
    int num,count=0;
    scanf("%d",&num);
    gets(mima);
    while(count<2)
    {
    if(strcmp(mima,password[num-1])==0)
    {printf("It's right!welcome...");break;}
    else
    {printf("please input password again:");
    gets(mima);
    count++;
    }
    if(count==2)
    printf("error");}
    getch();
}


为什么运行时输错两次  第三次就算输对了  结果也是“error” 其他情况都没问题

题目

这代码写的也太乱了  没法看

第三次时 count 不就等于2了吗 打印error了

int num,count=0;
scanf("%d",&num);
getchar();    //加一句getchar
gets(mima);

while(count<2)
    if(strcmp(mima,password[num-1])==0)
        {
            printf("It's right!welcome...");
            break;
         }
    else
      {
         printf("please input password again:");
         gets(mima);
         count++;
       }
    if(count==2)   /*应该是这样吧，这个在循环体外面吧？*/
    printf("error");
    getch();

#include<stdio.h>
#include<string>
int main()
{
    char *password[]=
    {"Cat","Mouse","Dog","Sugar","Water","Meat","Steel"};
    char mima[100];
    int num,count=0;
    scanf("%d",&num);
    gets(mima);
    while(count<4)
    {
    if(strcmp(mima,password[num-1])==0)
    {printf("It's right!welcome...");break;}
    else
    {printf("please input password again:");
    gets(mima);
    count++;
    }
    }
    if(count==3)
    printf("error");
   // getch();
    return 0;
}

#include <stdio.h>
#include <string.h>
void main()
{
    char *password[]={"cat","mouse","dog","sugar","water","meat","steel"},b[10];
    int n,i,count=0;
    printf("please input number\n");
    scanf("%d",&n);
    getchar();
    printf("please input password\n");
    for(i=1;i<=3;i++)
    {
        gets(b);
        if(strcmp(b,*(password+n-1))==0) { printf("It's right ! welcome\n");break;}
        else
        {
            count++;
            if(count==3) {printf("error\n");break;}
            else printf("please input password again\n");
        }
    }
}