这个是题目
Your roommate is not very familiar with Chinese Railway, and always get confused what the train number means. Now it's time to help him out.
In China, train number contains a lot of information. In this problem, you are supposed to answer the type of train. Train numbers are mainly numbered in following rules:
1. In this problem, you are given a train number containing 2~5 character, where the first character can be either digits or upper-case letter, and other characters are all digits.
2. If the first character is a letter, the train type is determined by the first letter:
'K': Rapid
'T' or 'Q': Express
'Z': SuperExpress
'D': EMUExpress
'G' or 'C': HighSpeed
3. If the first character is a digit, the train type is determined by the integer S the train number forms. To simplify the problem, you may assume:
1000 <= S < 6000: Semi-fast
S >= 6000: Local
And you may assume that no test case will contain any string that was not mentioned in the description.
Input
First line: number of test cases T;
2 ~ T+1 line: Train number.
Output
For each case, output the train type described before.
ATTENTION: Don't modify the names, or you will get WA, copying and pasting them are strongly recommended.
Sample Input
3
4419
Z61
G101

Sample Output
Semi-fast
SuperExpress
HighSpeed


这是我的程序
int main(int argc, char* argv[])
{   
    int m,i;
    char c;
    scanf("%d",&m);

    for(i=1;i<=m;i++)//我的问题是为什么进不去循环啊
    {
        getchar(c);
        switch(c)
        {
           case 'K':printf("Rapid");break;
           case 'T':case 'Q':printf("Express");break;
           case 'Z':printf("SuperExpress");break;
           case 'D':printf("EMUExpress");break;
           case 'G':case 'C':printf("HighSpeed");break;

           case '1':case '2':case '3':case '4':case '5':case '6':printf("Semi-fast"); break;
           default:printf("Local");
        }
        
    }
    return 0;
}

现在可以了，你看看吧！对了，记得在循环中用输入流记得要FFLUSH函数进行缓存处理！

#include <stdio.h>

int main(int argc, char* argv[])
{   
    int m,i;
    char c;
    scanf("%d",&m);
    fflush(stdin);
    for(i=1;i<=m;i++)//我的问题是为什么进不去循环啊
    {
        c=getchar();
        fflush(stdin);
        printf("c: %c\n",c);
        switch(c)
        {
           case 'K':printf("Rapid");break;
           case 'T':case 'Q':printf("Express");break;
           case 'Z':printf("SuperExpress");break;
           case 'D':printf("EMUExpress");break;
           case 'G':case 'C':printf("HighSpeed");break;

           case '1':case '2':case '3':case '4':case '5':case '6':printf("Semi-fast"); break;
           default:printf("Local\n");
        }
        
    }
    return 0;
}

学习了，谢谢

c=getchar();
switch(c)
感觉这样改就行呢没测试

#include <stdio.h>

int main(int argc, char* argv[])
{  
    int m,i;
    char c;
    scanf("%d",&m);
    getchar();//接收回车符
    //fflush(stdin);
    for(i=1;i<=m;i++)//我的问题是为什么进不去循环啊
    {
        c=getchar();//接收字符
        //fflush(stdin);
        printf("c: %c\n",c);
        getchar();//接收回车符，它接收的是c=getchar();后你敲的回车符
        switch(c)
        {
           case 'K':printf("Rapid\n");break;
           case 'T':case 'Q':printf("Express");break;
           case 'Z':printf("SuperExpress");break;
           case 'D':printf("EMUExpress");break;
           case 'G':case 'C':printf("HighSpeed");break;

           case '1':case '2':case '3':case '4':case '5':case '6':printf("Semi-fast"); break;
           default:printf("Local\n");
        }
       
    }
    return 0;
} 

真是太感谢啦！真的可以了
不过我还是没懂为什么一定要这样啊，我怎么觉得以前没有听说过也没有用过啊？？

真是太感谢啦！真的可以了
不过我还是没懂为什么一定要这样啊，我怎么觉得以前没有听说过也没有用过啊？？

是说那个缓存问题吗？那是因为你多次进行输入操作的话，用scanf或者getchar的话他是先放入缓存的，还不懂的话就百度下fflush！

进步了循环吗，可以啊，我在vc中用debug调试的。

为什么要接收回车呢？scanf中不是回车可以表示输入结束吗？