#include <stdio.h>
int main(void)
{
    float weight;     
    //用户的体重
    float value；     
    //相等重量的铑的价值
    printf("Are you worth your weight in rhodium?\n");
    printf("let's check it out.\n");
    printf("Please enter your weight in pounds: ");     
    //从用户处获取输入
    scanf("%f", &weight);
    //假设铑为每盎司770美元
    //14.5833把常衡制的英镑转换为金衡制的盎司
    value = 770 * weight * 14.5833;
    printf("Your weight in rhodium is worth $%.2f.\n". value);
    printf("You are easily worth that! If rhodium prices drop, \n");
    printf("eat more to maintain your value.\n");
    return 0;
详细请见《c primer plus》 第三章开头例题
编译有一个错误 何解？

#include <stdio.h>
int main(void)
{
    double weight;     
    //用户的体重
    double value；     
    //相等重量的铑的价值
    printf("Are you worth your weight in rhodium?\n");
    printf("let's check it out.\n");
    printf("Please enter your weight in pounds: ");     
    //从用户处获取输入
    scanf("%f", &weight);
    //假设铑为每盎司770美元
    //14.5833把常衡制的英镑转换为金衡制的盎司
    value = 770 * weight * 14.5833;
    printf("Your weight in rhodium is worth $%.2lf.\n"， value);
    printf("You are easily worth that! If rhodium prices drop, \n");
    printf("eat more to maintain your value.\n");
    return 0;
}  //缺少括号
还不知道哪里有个全角分号  忘了

下面的“｝”是没有复制上 为什么要用double啊 我看书上是float

value = 770 * weight * 14.5833;
估计2个FLOAT类型相乘  编译器认为其结果必为DOUBLE型

double改了，试了，还是不对。纠结啊

#include <stdio.h>
int main(void)
{
    double weight;     
    //用户的体重
    double value;     
    //相等重量的铑的价值
    printf("Are you worth your weight in rhodium?\n");
    printf("let's check it out.\n");
    printf("Please enter your weight in pounds: ");     
    //从用户处获取输入
    scanf("%f", &weight);
    //假设铑为每盎司770美元
    //14.5833把常衡制的英镑转换为金衡制的盎司
    value = 770 * weight * 14.5833;
    printf("Your weight in rhodium is worth $%.2lf.\n", value);
    printf("You are easily worth that! If rhodium prices drop, \n");
    printf("eat more to maintain your value.\n");
    return 0;
}
这样可以编译啊

Your weight in rhodium is worth $%.2lf.\n", value 为什么是%21f 而不是%.2f 求解

float  对应 F
DOUBLE 对应 LF