#define X(a,b,c) x=a*cos(b*c*pi/180-pi/2)+300;
#define Y(a,b,c) y=a*sin(b*c*pi/180-pi/2)+240;
#define d(a,b,c) X(a,b,c);Y(a,b,c);line(300,240,x,y) /*定义……*/

估计是要计算时钟时针分针秒针  的偏转角度

定义一些红  减少代码量

虽然不懂，境界还没到。。。。也冒个泡。

明显是时针分针的角度计算
具体应该分析一下代码

#define X(a,b,c) x=a*cos(b*c*pi/180-pi/2)+300; //比如这个，是画哪根针啊？
x=a*cos(b*c*pi/180-pi/2)+300   这个运算怎么就能正确表示钟表转速啊？？？

#include<graphics.h>
#include<math.h>
#include<dos.h>
#define PI 3.1415926
#define mid_x 320    /*定义钟表中心坐标*/
#define mid_y 240
 
int main()
{
    int graphdriver=0,graphmode;
    int end_x,end_y;
     struct time curtime;
     float th_hour,th_min,th_sec;
     initgraph(&graphdriver,&graphmode,"e:\\TC");
     setbkcolor(0);
     while(! kbhit())/*有键盘输入时退出*/
     {      
         /*画表盘*/
         setcolor(14);
          circle(mid_x,mid_y,150);
          circle(mid_x,mid_y,2);
         gettime(&curtime);   /*得到当前系统时间*/
            /*以下三行计算表针转动角度，以竖直向上为起点，顺时针为正*/
           th_sec=(float)curtime.ti_sec*0.1047197551;                 /*2π/60=0.1047197551*/
           th_min=(float)curtime.ti_min*0.1047197551+th_sec/60.0;
           th_hour=(float)curtime.ti_hour*0.523598775+th_min/12.0;    /*2π/12=0.5235987755*/
           /*画时针*/
           end_x=mid_x+70*sin(th_hour);
          end_y=mid_y-70*cos(th_hour);
          setcolor(5);
          line(mid_x,mid_y,end_x,end_y);   
           /*画分针*/
           end_x=mid_x+110*sin(th_min);
          end_y=mid_y-110*cos(th_min);
         setcolor(5);
          line(mid_x,mid_y,end_x,end_y);  
           /*画秒针*/
           end_x=mid_x+140*sin(th_sec);
          end_y=mid_y-140*cos(th_sec);
          setcolor(5);
          line(mid_x,mid_y,end_x,end_y);
           sleep(1);      /*延时一秒后刷新*/
           cleardevice();
       }
     closegraph();
     return 0;
}
这个是全部……

啊……把另外一个钟表发出来了……

怎么算的啊，能解释具体点吗

你代码中又没用到定义的宏，计算角度的你自己不是已经注释的挺好的吗

根据你的代码应该是这样计算的吧

/*画时针*/
#define X(a,b) 300-(a)*sin(b);//x轴终点坐标
#define Y(a,b) 240-(a)*cos(b);//y轴终点坐标

line(mid_x,mid_y,X(70,th_hour),Y(70,th_hour));