以下程序完成将S2的字符串连接到S1中去，即将两个字符串合并的功能。

void main()

{char s1[80],s2[40];

 int i=0,j=0;

 printf("\nInput string1:");

 scanf("%s",s1);

 printf("\nInput string2:");

 scanf("%s",s2);

 while(s1[i]!='\0')

       s1=s1      ;

 while(s2[j]!='\0')

      s2=s2               ;

         s1=s1+s2        ;

 printf("The new string is:%s",s1);}


[ 本帖最后由 身不由己 于 2011-5-14 22:04 编辑 ]

#include <iostream>
#include <string>

using namespace std;

int wmain(void)
{
    string s1;
    string s2;

    cout << "\nInput string1:";
    cin >> s1;

    cout << "\nInput string2:";
    cin >> s2;

    s1.append(s2);

    cout << "The new string is: " << s1 << endl;


    return 0;
}

#include <stdio.h>

int main(void)
{
    char s1[80],s2[40];
    int i=0,j=0;

    printf("\nInput string1:");
    scanf("%s",s1);

    printf("\nInput string2:");
    scanf("%s",s2);

    while(s1[i]!='\0')
    {
        ++i;
    }

    while(s2[j]!='\0')
    {
        s1[i++] = s2[j++];
    }
    s1[i] = 0;

    printf("The new string is:%s\n",s1);

    return 0;

}

谢谢斑竹

没事~~

最后那不是s[i+1] = 0;???

为什么非要用 int main(void)  最后来个 return o

这个用数据结构也能写