写一个函数，输入十六进制，输出相应的十进制？帮帮忙看看

#include "stdio.h"

void print(int x)
{   
    printf("十六进制结果：%x\n",x);
}

void main()
{ int n;
 printf("请输入一个数,它将以十六进制输入：");
 scanf("%d",&n);
 print(n);
}

      #include"stdio.h"
      #include"string.h"
      void zhuhuan(int dnum)
      {
          int n,i=0;
          int p;
         char a[100],*hex;
          hex=a;

         while(dnum)
         {
            p=dnum%16;
            if(p>=0&&p<=9)
            {
             *(hex+i)=p+'0';
             i++;
            }
            else
            {
               *(hex+i)=p-10+'a';
                i++;
            }
            dnum/=16;
         }
         *(hex-1)='0';

         
        while(i)
         {
           --i;
          printf("%c",*(hex+i));
         }

          }
      main()
      {
          int m;
          printf("input num:\n");
          scanf("%d",&m);
          zhuhuan(m);
         
      }

貌似不对

    不可能吧，我的编译器是win-TC。