给文本加密
我想那个数组循环这和每个数异或后存入文件，怎么执行过程那么奇怪。。。
#include <stdio.h>
#include <conio.h>
int mima[3]={15,48,32};
int jiami()
{     int ch,dh,i=-1;
      FILE *fp1,*fp2;
      fp1=fopen("e:\\as\\ds.txt","rb");
      if(fp1==NULL)
           printf("can not open the file!!");
      fp2=fopen("e:\\as\\jiami.txt","wb");
      if(fp2==NULL)
                   printf("can not open the file!!\n");
      ch=fgetc(fp1);
      while(!feof(fp1))
       {  i=i+1;
          dh=ch^(mima[i]);  
          printf("%  d   ",mima[i]);
          printf("jiami");
              if(i==2)       //到第三个数时回到第一个数
              {i==-1;
              }
          fputc(dh,fp2);
          ch=fgetc(fp1);
       }
       fclose(fp1);
       fclose(fp2);
      
}
int jiemi()
{
      int ch,dh,i=-1;
      FILE *fp1,*fp2;
      fp1=fopen("e:\\as\\jiami.txt","rb");
      if(fp1==NULL)
           printf("can not open the file!!");
      fp2=fopen("e:\\as\\jiemi.txt","wb");
      if(fp2==NULL)
                   printf("\ncan not open the file!!\n");
      ch=fgetc(fp1);
      while(!feof(fp1))
       {  i=i+1;
          dh=ch^(mima[i]);
          printf("%  d  ",mima[i]);
          printf("jiemi");
               if(i==2)
               {i==-1;
               }
          fputc(dh,fp2);
          ch=fgetc(fp1);
       }
       fclose(fp1);
       fclose(fp2);
      
}
main()
{     printf("\n");
      jiami();
      printf("\n");
      jiemi();
      getch();
      }

原理是没有问题的，本想帮你修习一下，可是字体不兼容。自己好好调试吧

              if(i==2)       //到第三个数时回到第一个数
              {i==-1;
              }
i==-1改为i=-1