线性表>.< 扑朔迷离!
#define ERROR 0 #define OK 1
struct STU{
char name[20];
char stuno[10];
int age;
int score;
}stu[50];
struct LIST
{
struct STU stu[50];
int length;
}L;
int printlist(struct LIST L)
{
int i;
printf("name stuno age score\n");
for(i=0;i<L.length;i++)
printf("%s %s\t%d\t%d\n", L.stu[i].name, L.stu[i].stuno,
L.stu[i].age, L.stu[i].score);
printf("\n");
}
int listinsert(struct LIST *L,int i,struct STU e)
{
struct STU *p,*q;
if (i<1||i>L->length+1) return ERROR;
q=&(L->stu[i-1]);
for(p=&L->stu[L->length-1];p>=q;--p)
*(p+1)=*p;
*q=e;
++L->length;
return OK;
}/*ListInsert Before i */
main()
{
struct STU e;
L.length=0;
strcpy(e.name,"zmofun");
strcpy(e.stuno,"100001");
e.age=80;
e.score=1000;
listinsert(&L,1,e);
printlist(L);
printf("List length now is %d.\n\n",L.length);
strcpy(e.name,"bobjin");
strcpy(e.stuno,"100002");
e.age=80;
e.score=1000;
listinsert(&L,1,e);
printlist(L);
printf("List length now is %d.\n\n",L.length);
}
------------------------问题-----------------------
如您所见....
main函数里面,有length=0的赋值语句
那么就不满足int listinsert函数里面的for循环语句了.怎么还能执行?
另外printlist函数里面i的值是谁传递的?
这一句*(p+1)=*p;是不是多余的?
