String[a.length][2] ，String[]a={"a","b","c","d"};
public String[][] isAsslaw(String[] a, String[][] b) {
String[][] c= new String[a.length][2];
for (int i = 0; i < b.length; i++) {
for (int j = 0; j < b.length; j++) {
for (int k = 0; k < a.length; k++) {
int m = suffix(a, b[i][j]);// 利用suffix方法来求得m，n
int n = suffix(a, b[j][k]);
if (b[m][k] != b[i][n])
return c;
}
}
}
return c;
}
现在我要把m,k,i,n的值按照顺序（现在行后列）放在这个二维数组中。