题目：
  两个乒乓球队进行比赛，各出3人，甲队为A,B,C，3人，乙队为X,Y,Z，3人。已抽签觉定比赛名单，A说他不和X比，C说他不和X,Z比。请编程序找出三对赛手的名单。
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 我这有个已经编号的。征求其他答案。编的简单易懂就行了。
#include"stdio.h"
#include"conio.h"
void mian()
{
char i,j,k;
for (i='x';i<='z';i++;)
 {
  if (i!=j)
  for(k='x';k<='z';k++)
   {
     if(i!=k&&j!=k)
      {
        if(i!='x'&&k!='x'&&k!='z')
         printf("order is a --%c\tb--%c\tc--%c\n",i,j,k);
       }
     }
  }
}

An easy problem,but I think it's your homework,isn't it?
If my idea is wrong,I could write one for you and I don't ask you for anything,but if it is sure your homework,you should finish it by yourself.
Of course,if you need help when you are doing your homework,you can call me,and I'll help you if you pay some money for my knowledge and work.

[[it] 本帖最后由 orzorz 于 2008-6-27 14:59 编辑 [/it]]

Sorry.I'll modify it.Thanks

Maybe you are right,I should do it by myself.

Thanks!

[[it] 本帖最后由 单向路 于 2008-6-28 13:11 编辑 [/it]]

But I want to know  why you ask me that question ?
There are some users do it like that,why don't you say that?
Is the question of  my article title?

#include<stdio.h>
void main(){
int x,y,z;
int a,b,c;
if(c!=x && c!=z){
c=y;
}if(a!=x){
a=z;
b=x;
}
}

又是英文的。。呜...........

#include"stdio.h"
#include"conio.h"
void mian()
{
char i,j,k;
for (i='x';i<='z';i++;)
{
   for (j='x';j<='z';j++;)
     {
       if (i!=j)
        for(k='x';k<='z';k++)
         {
           if(i!=k&&j!=k)
            {
              if(i!='x'&&k!='x'&&k!='z')
               printf("order is a --%c\tb--%c\tc--%c\n",i,j,k);
             }
        }
     }
  }
}

恩 确实错了  少了一个for循环
呵呵  多谢提醒