在服务器端MIDlet中的startApp()方法中代码如下：
protected void startApp() throws MIDletStateChangeException {
        try {
            ServerSocketConnection ssc=(ServerSocketConnection)Connector.open("Socket://:1234");
            System.out.println("aaa");
            SocketConnection sc=(SocketConnection)ssc.acceptAndOpen();
        } catch (IOException e) {
            
            e.printStackTrace();
        }

    }

但是运行后却出现了如下异常：
java.lang.ClassNotFoundException: com/sun/midp/io/j2me/Socket/Protocol
    at javax.(+277)
    at javax.(+15)
    at javax.(+6)
    at javax.(+5)
    at ServerMIDlet.startApp(+5)
    at javax.microedition.midlet.MIDletProxy.startApp(+7)
    at com.sun.midp.midlet.Scheduler.schedule(+270)
    at com.sun.midp.main.Main.runLocalClass(+28)
    at com.sun.midp.main.Main.main(+80)
java.lang.ClassNotFoundException: com/sun/midp/io/j2me/Socket/Protocol
    at javax.(+277)
    at javax.(+40)
    at javax.(+6)
    at javax.(+5)
    at ServerMIDlet.startApp(+5)
    at javax.microedition.midlet.MIDletProxy.startApp(+7)
    at com.sun.midp.midlet.Scheduler.schedule(+270)
    at com.sun.midp.main.Main.runLocalClass(+28)
    at com.sun.midp.main.Main.main(+80)
javax. The requested protocol does not exist Socket://:1234
    at javax.(+72)
    at javax.(+6)
    at javax.(+5)
    at ServerMIDlet.startApp(+5)
    at javax.microedition.midlet.MIDletProxy.startApp(+7)
    at com.sun.midp.midlet.Scheduler.schedule(+270)
    at com.sun.midp.main.Main.runLocalClass(+28)
    at com.sun.midp.main.Main.main(+80)

天天说API的，但是API到底是什么东西啊，烦请大侠告知一二。

自己顶了，高手快来帮忙解决，谢谢！！！
在线等........

晕，人都哪里去了，怎么没人来帮我一下啊，跪求解答~！！！

ServerSocketConnection ssc=(ServerSocketConnection)Connector.open("Socket://:1234");
..............("Socket://:1234");...........这里面的Socket换成socket试试
反正你这个点是错的

API即是应用程序接口

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