我自己弄了一道题来做,结果程序执行出错.

题目是:
设有线性表LA=(3,5,8,11)和LB=(2,6,8,9,11,15,20)
若LA和LB分别表示两个集合A和B ,求新集合A=AUB('并"操作,相同元素不保留),预测榆出A=(3,5,8,11,2,6,9,15,20)


各位大侠请帮忙看看哪里出错了
小弟初学,拜求详解...

#include<stdio.h>
void main()
{
    int i,t,k;
    int a[3],b[6],n[10];

    printf("请输入线性表LA中的数值:\n");
    for (i=0;i<=3;i++)
    scanf("%d",&a[i]);
    printf("\n");

    printf("请输入线性表LB中的数值:");
    for (i=0;i<=6;i++)
    scanf("%d",&b[i]);
    printf("\n");

    printf("新集合A=AUB的数值:\n");
    for (i=0;i<=3;i++)
    {
        printf("%d",a[i]);
    }

    k=4;
    for (i=0;i<=6;i++)
          {
                 for (t=0;t<=3;t++)

                 {
        
                     if (b[i]==a[t])
                     {
                          i++;break;
                          
                     }
            
                      n[k]=b[i];
                         k++;
                      printf("%d,",n[k]);
                 }
          }
          printf("\n");
}

数组越界