4位数猜测，不对就给出提示A表示位置和数字都对，B表示数字对位置不对

在线等答案






#include <math.h>
#include <stdio.h>
void main(void)
{
int answer[4]={1,3,5,2},guess,a,b,times=0,i,j;    /*初始化被猜答案为1352*/
printf("please guess\n");
while(a!=4)
{                                                 /*进入猜数字循环*/
a=0;
b=0;
times++;                                          /*猜测次数加1*/
printf("%d",times);                               /*显示猜测次数*/
scanf("%d",&guess);                               /*数取玩家输入数字*/
for(i=3;i>-1;i--)
{                                                 /*开始循环*/
for(j=0;j<4;j++)
{
if((int)(guess/pow10(i))==answer[j])
if(i+j==3)                                        /*如果位置相同A加1*/
a=a+1;
else
b=b+1;                                            /*如果位置不同B加1*/
}
}
guess=guess-(int)(guess/pow10(i)*pow10(i)
}                                                 /*对比下一位猜测数字*/
printf("%dA%dB\n",a,b);                           /*显示本次猜测AB正确性*/
}


就是程式结果对，你的算法也不行，改了改你的程式，自己体会一下吧,有时候多加几个变量程序效率更高,还有这个程序没有对非法输入进行判断以及重复数字的判断（应该不充许吧？），自己加吧.

#include <stdio.h>
void main(void)
{
    int answer[4]=
    {
        1,3,5,2
    }
    ,guess,a,b,times=0,i,j,GUESS1[4],Errors=0 ;
    /*初始化被猜答案为1352*/
   
    printf("please guess\n");
    while(1)
    {
        printf("%d    ",times);
        /*显示猜测次数*/
        scanf("%d",&guess);
        i=3 ;
        a=0,b=0 ;
        while(guess)
        {
            GUESS1[i--]=guess%10 ;
            /*将未尾数赋给GUESS[i]*/
            guess/=10 ;
            /*guess缩位*/
            if(guess&&i<0)
            {
                printf("输入超过4位！请重输！\n\n");
                Errors=1 ;
                break ;
            }
        }
        if(!Errors)
        {
            for(i=0;i<4;i++)
            {
               
                for(j=0;j<4;j++)
                {
                    if(i==j)
                    {
                        if(GUESS1[i]==answer[j])a++;
                    }
                    else
                    {
                        if(GUESS1[i]==answer[j])b++;
                    }
                }
            }
            printf("%dA%dB\n",a,b);
            /*显示本次猜测AB正确性*/
            times++;
        }
        else
        {
            Errors=0 ;
        }
    }
}

谢谢先

大哥，错的啊，无法编译

没错吧,我试了一下.不过如果输入非法数字就会陷入死循环.

#include <math.h>
#include <stdio.h>
void main(void)
{
int answer[4]={1,3,5,2},guess,a,b,times=0,i,j;    /*初始化被猜答案为1352*/
printf("please guess\n");
while(a!=4)
{                                                 /*进入猜数字循环*/
a=0;
b=0;
times++;                                          /*猜测次数加1*/
printf("%d",times);                               /*显示猜测次数*/
scanf("%d",&guess);                               /*数取玩家输入数字*/
for(i=3;i>-1;i--)
{                                                 /*开始循环*/
for(j=0;j<4;j++)
{
if((int)(guess/pow10(i))==answer[j])
if(i+j==3)                                        /*如果位置相同A加1*/
a=a+1;
else
b=b+1;                                            /*如果位置不同B加1*/
}
}
guess=guess-(int)(guess/pow10(i))*pow10(i);
}                                                 /*对比下一位猜测数字*/
printf("%dA%dB\n",a,b);                           /*显示本次猜测AB正确性*/
}



我的我修改了，但是和你有同样的问题就是死循环，今天搞定，

死循环问题很好解决，去了解一下scanf的返回值的意义，还有个 fflush （）的清流函数。

你的程序效率太差,空间换效率是编程中常常用到方法.

是啊，正在修改当中，新人嘛！