不知道怎么做～还是自己胡乱做了～
自己都知道和题目不副～但也不知道怎么做
帮帮新手了～

#include<stdio.h>
int main()
{
char s[1000],ch;
int i;
while((ch=getchar())!=EOF)
{
if(ch!='r'||ch!='R')
{
ch=s[i++];
}
else
{
printf("%d",i);
}
}
system("PUAES");
return 0;
}

man strchr

SYNOPSIS
#include <string.h>

char *strchr(const char *s, int c);

char *strrchr(const char *s, int c);

DESCRIPTION
The strchr() function returns a pointer to the first occurrence of the
character c in the string s.

The strrchr() function returns a pointer to the last occurrence of the
character c in the string s.

Here "character" means "byte"; these functions do not work with wide or
multi-byte characters.

RETURN VALUE
The strchr() and strrchr() functions return a pointer to the matched
character or NULL if the character is not found.

斑竹～～小弟看不大懂呀～
是英文的吗？

include<stdio.h>

int main(){
char s[1000];
int i;
scanf("%s", s);
for(i=0; s[i]!='\0'; i++){
if(s[i]=='r' || s[i]=='R'){
printf("the position is: %d", i);
break;
}
}
return 1;
}

[此贴子已经被作者于2006-11-7 18:25:03编辑过]

#include<stdio.h>
int main()
{
char s[1000];
int i=0;
scanf("%s",s);
while(s[i]!=0)
{
if(s[i]=='r'||s[i]=='R')
{
printf("%d",i+1);
}
i++;
}
getch();
return 0;
}

#include<stdio.h>
#include<string.h>
void main()
{
char s[1000];
scanf("%s", s);
char *a;
printf("%d",(a=strchr(s,'r')<strchr(s,'R')?strchr(s,'r'):strchr(s,'R'))-s);
}

[此贴子已经被作者于2006-11-7 21:24:14编辑过]

char c;
int i=1;
while((c=getchar())!='\n')
{
if(c=='r'||c=='R')
{
printf("%d\n",i);
break;
}
i++;
}

似乎明白了~~~
谢谢各位了