求1000之内的所有完数
#include <iostream>
using namespace std;
int main()
{
    cout << "完数有:";
    int s = 0;
    for (int i = 2; i < 1000; i++)
    {
        for (int j = 1; j < i; j++)
        {
            if (i % j == 0)
                s += j;         
        }
        if(i == s)
            cout << i << "  ";
    }
    cout << endl;
}

好的好的，我记住了，谢谢