#include<stdio.h>
#include<stdlib.h>
#include<string.h>
// 
typedef struct player{
    int number;
    char name[20];
    struct player*next;
}Player;
Player*game(void);
int main ()
{
    Player *head;
    head=game();
    printf("%s",head->name);
    return 0;
} 
Player*game(void)

 {
    Player *p1=(Player*)malloc(sizeof(Player));
    Player *p2=(Player*)malloc(sizeof(Player));
    Player *p3=(Player*)malloc(sizeof(Player));
    if(p1!=NULL){
        p1->number=1;
        strcpy(p1->name,"战士1"); 
    }
    if(p1!=NULL){
        p2->number=2;
        strucp(p2->name,"战士2"); 
    }
    if(p1!=NULL){
        p3->number=3;
        strcpy(p3->name,"战士3");
    }

    //连接节点 
    p1->next=p2;
    p2->next=p3;//不用p2->next=&p3 因为p3已经是typedef struct player的指针变量存储的就是地址古不需要再取地址 
    p3->next=NULL;//创建尾节点 
    Player*head=p1;//创建链表的头节点 
    return head;
}

C:AppData\Local\Temp\cccWaGe9.o    创建简单的单向链表（改为函数形式）.c:(.text+0xb8): undefined reference to `strucp'
D:\c语言\程序\链表\collect2.exe    [Error] ld returned 1 exit status

if哪里是p1,p2,p3

谢谢