想问下如何画出红圈处点的轨迹
Const pi = 3.1415926
Dim angle As Integer
Private Sub Form_Load() '调整空间尺寸，位置及初始参数
Me.ScaleMode = 2
Me.Caption = "I型曲柄滑块"
Me.Width = 10000
Me.Height = 7000
Picture1.ScaleMode = 2
Picture1.AutoRedraw = True
Picture1.Move 0, 0, Me.ScaleWidth, 1500
Command1.Caption = "开始(&B)"
Command1.Move 20, 260, 70, 30
Label1.Caption = "速度:"
Label1.Move 120, 170, 100, 30
HScroll1.Min = 1
HScroll1.Max = 20
HScroll1.Move 160, 260, 140, 30
Timer1.Interval = 20
Timer1.Enabled = False
End Sub
Private Sub Command1_Click()
Timer1.Enabled = Not Timer1.Enabled
If Timer1.Enabled Then
Command1.Caption = "暂停(&S)"
Else
Command1.Caption = "开始(&B)"
End If
End Sub
Sub draw(ByVal ox As Integer, ByVal oy As Integer, ByVal orad As Integer) 'ox,oy圆心坐标,orad半径
angle = (angle + HScroll1.Value) Mod 360
xo = ox + orad * Cos(angle * pi / 180) 'ox,oy圆心坐标,orad半径
yo = oy - orad * Sin(angle * pi / 180)
xs = Sqr((3 * orad) ^ 2 - 10 ^ 2) + xo '滑块的左边界x坐标，连杆长度取4*orad,滑块高度取20(像素)?
xz = 3 * Sqr((3 * orad) ^ 2 - 10 ^ 2) + xo
Picture1.BackColor = Picture1.BackColor
Picture1.DrawStyle = 0 '实线
Picture1.DrawWidth = 2 '线宽2
Picture1.Line (ox + 2 * orad, oy + 10)-(ox + 6 * orad, oy + 10) '壁面
Picture1.Line (ox, oy)-(xo, yo) '连接圆心与圆周上的铰链点
Picture1.Line (xs, oy)-(xo, yo), vbBlue '连接滑块与圆周上的铰链点
Picture1.Line (xz, 3 * oy - 2 * yo)-(xs, oy), vbBlue
Picture1.FillStyle = 1 '透明填充
Picture1.Circle (ox, oy), orad '画圆
Picture1.FillStyle = 0 '实体填充
Picture1.FillColor = vbWhite '圆心
Picture1.Circle (ox, oy), 5
Picture1.FillColor = vbGreen '圆周上的铰接点
Picture1.Circle (xo, yo), 4
Picture1.FillColor = vbRed '滑块
Picture1.Line (xs - 20, oy - 10)-(xs + 20, oy + 10), , B
Picture1.DrawStyle = 2 '虚线
Picture1.DrawWidth = 1 '线宽1
For i = 0 To 9 '表示壁面的虚线
Picture1.Line (i * 3 * orad / 10 + ox + 2 * orad - 5, oy + 10)-(i * 3 * orad / 10 + ox + 2 * orad + 20 - 5, oy + 20)
Next
End Sub
Private Sub Timer1_Timer() '画
draw 60, 160, 40
End Sub
源码有了，请大佬们指点一下
