#include<stdio.h>
char *find_char(char const *source,char const *chars){
    char *str=source;
    char *strings=chars;
    if(source || chars)
        return NULL;
    while(str){
        for(;strings;strings++){
            if(*str==*strings)
                return strings;
        }
        str++;
    }
    return NULL;
}
int main(){
    char const a="adfaddfdfdffgda";
    char const b="134f;poljklj";
    printf("%p",find_char(a,b));
}
这是什么原因？

应该怎么该
#include<stdio.h>
char *find_char(char const *source,char const *chars){
    char *str=source;
    char *strings=chars;
    if(source==NULL || chars==NULL)
        return NULL;
    while(*str=='\0'){
        for(;*strings=='\0';strings++){
            if(*str==*strings)
                return strings;
        }
        str++;
    }
    return NULL;
}
int main(){
    char const a[]="adfaddfdfdffgda";
    char const b[]="134f;poajklj";
    printf("%d",find_char(a,b));
}

会了，谢谢大佬。

592986650

#include<stdio.h>
char *find_char(char const *source,char const *chars){
    char *str=source;
    char *strings=chars;
    if(source==NULL || chars==NULL)
        return NULL;
    while(*str!='\0'){
        for(;*strings!='\0';strings++){
            if(*str==*strings)
                return strings;
        }
        str++;
    }
    return NULL;
}
int main(){
    char const a[]="adfaddfdfdffgda";
    char const b[]="134f;poajklj";
    printf("%p",find_char(a,b));
}

这个可以