题目是输入一个字符串，判断是否是合法邮箱（格式正确即可，不管是否真的存在）输入的只能是字母、数字、下划线、@以及.五种， @前后只能是字母或者数字，而且.后只能是com， 是则输出YES ，否则输出NO。
#include<stdio.h>
#include<string.h>
int main()
{
    char em[50];
    int i=0,len;
    int dui = 0,aite = 0,qita = 0;
    scanf("%s",em);
    len = strlen(em);
    while(1){
        if(em[0] == '@'){
            printf("NO");
            break;
        }
        while(em[i] != '@'){
            if(em[i]=='_' || (em[i]>='a' && em[i]<='z') || (em[i]>='A' && em[i]<='Z') || (em[i]>='0' && em[i]<='9')) dui=1;
            else qita = 1;        
            i++;
            if(i==len - 1){
                printf("NO");
                break;
            }
        }
        if(i==len - 1){
            break;
        }
        if(((em[i-1]>='a' && em[i-1]<='z') || (em[i-1]>='A' && em[i-1]<='Z') || (em[i-1]>='0' && em[i-1]<='9')) && ((em[i+1]>='a' && em[i+1]<='z') || (em[i+1]>='A' && em[i+1]<='Z') || (em[i+1]>='0' && em[i+1]<='9'))){
            dui = 1;
        }
        else{
            printf("NO");
            break;
        }
        if(qita == 1){
            printf("NO");
            break;
        }
        qita = 0;
        i++;
        while(em[i] != '.'){
            if(em[i]=='_' || (em[i]>='a' && em[i]<='z') || (em[i]>='A' && em[i]<='Z') || (em[i]>='0' && em[i]<='9')) dui=1;
            else{
                qita = 1;   
                break;
            }        
            i++;
        }   
        if(qita == 1){
            printf("NO");
            break;
        }
        if((em[i+1] != 'c' || em[i+2]!= 'o'|| em[i+3] != 'm') || em[i+4] != '\0'){
            printf("NO");
            break;   
        }
        else {
            printf("YES");
            break;   
        }
    }
    return 0;
 }