做到一道题目要求3*5二维数组，求每组平均数，所有数据平均数，找出最大值。我用三个子函数按顺序分别处理，但是结果很尴尬，乱码了......个人感觉是不是二维数组在子函数调用时出问题了，需要将二维数组当一维数组处理，求大佬解释一下


#include<stdio.h>
double AVER1(double a[][5],int m,int n);
double AVER2(double a[][5],int m,int n);
double MAX(double a[][5],int m,int n);
int main()
{
    int line,row;
    double average1,average2,max;
    double a[3][5];
    printf("*******************************\n");
    printf("This program will finish 3 tasks\n");
    printf("*******************************\n");
    for(line=0;line<3;line++)
    {
        for(row=0;row<5;row++)
        {
            printf("please enter %d line,%d row number:",line+1,row+1);
            scanf("%f",&a[line][row]);
            while(getchar()!='\n')
                continue;
        }
    }
    average1=AVER1(a,3,5);
    average2=AVER2(a,3,5);
    max=MAX(a,3,5);
    printf("average1=%.4f\naverage2=%.4f\nmax=%.4f",average1,average2,max);
    return 0;
}
double AVER1(double ar[][5],int m,int n)
{
    double aver,sum;
    int line,row;
    for(line=0;line<m;line++)
    {
        sum=0;
        for(row=0;row<n;row++)
        {
            sum+=ar[line][row];
        }
        printf("%d line sum=%.4f,average=%.4f\n",line+1,sum,sum/5);
    }
    return sum/5;
}
double AVER2(double ar[][5],int m,int n)
{
    double aver,sum;
    int line,row;
    for(line=0,sum=0;line<m;line++)
    {
        for(row=0;row<n;row++)
        {
            sum+=ar[line][row];
        }
    }
    printf("all number sum=%.4f,average=%.4f\n",sum,sum/15);
    return sum/15;
}
double MAX(double ar[][5],int m,int n)
{
    double max;
    int line,row;
    max=ar[0][0];
    for(line=0;line<m;line++)
    {
        for(row=0;row<n;row++)
        {
            if(max<ar[line][row])
                max=ar[line][row];
            else
                ;
        }
    }
    return max;
}

(°_°)…看来我记错了，把输出是％f当成输入也是％f，面壁思过。题目要求三个函数，我也不想用这么多函数的，打扰大佬休息了，我继续赶作业……