求2到1000之间所有的完数，要求每行输出5个。

#include<stdio.h>
int main(void)
{
    int x,i,sum=0,count=0;
    for(x=2;x<=1000;x++)
    {
        for(i=1;i<x;i++)
        {
            if(x%i==0)
                sum+=i;
        }
        if((sum==x)&&(count%5!=0))
        {   
            printf("%d ",x);
            count++;
        }
        else if((sum==x)&&(count%5==0))
        {
            printf("%d\n",x);
            count++;
        }
    }
}