编程求10到999之间满足各位数字之和是5的所有数。要求每行输出5个。

#include<stdio.h>
int main(void)
{
    int x,count=0;
    for(x=10;x<=99;x++)
    {
        if((x/10+x%10==5)&&(count%5==0))
        {
            printf("%d\n",x);
            count++;
        }
        else if((x/10+x%10==5)&&(count%5!=0))
        {
            printf("%d ",x);
            count++;
        }
    for(x=100;x<=999;x++)
    {
        if((x/100+x/10%10+x%10==5)&&(count%5==0))
        {
            printf("%d\n",x);
            count++;
        }
        else if((x/100+x/10%10+x%10==5)&&(count%5!=0))
        {
            printf("%d ",x);
            count++;
        }
   
    }
   
}