#include <cstdio>  
#include <queue>
#include <algorithm>
#include <vector>
#include <string>
using namespace std;
const int maxn = 100;   
bool Isnodroot[maxn] = {false};
struct Node{
//    int data;c
    int lchild;
    int rchild;
}node[maxn];  
int n, num = 0;
void print(int index) {
   
    printf("%d",index);
    num++;
    if(num < n) printf(" ");
    else printf("\n");
   
}
void inorder(int root) {
    if(root == -1)   return;
    inorder(node[root].lchild);
    print(root);
    inorder(node[root].rchild);
}

void bfs(int root){
    queue<int> q;
    q.push(root);
    while( !q.empty() ){
        int front = q.front();
        
        q.pop();
        print(front);
        if(node[front].lchild != -1)  {
            q.push(node[front].lchild);
        }
        if(node[front].rchild != -1)  
        {
            q.push(node[front].rchild);
        }
    }
   
}
void postInvert(int root){
    if(root == -1)  return;
    postInvert(node[root].lchild);
    postInvert(node[root].rchild);
    swap(node[root].lchild, node[root].rchild);
}
int nodroot(){
    for(int i = 0; i < n; i++) {
        if(Isnodroot[i] == false) return i;
    }
}
int str2Num(char c) {
    if(c == '-') return -1;
    else{
        Isnodroot[c - '0'] = true;
        return c - '0';
    }
}

int main()
{
    freopen("1.txt","r",stdin);
    string a;
    scanf("%d", &n);
    for(int i = 0; i < n; i++) {
        
        
        scanf("%s",&a);
        getchar();
        if(a[0] != '-') {
            node[i].lchild = a[0] - '0';
            Isnodroot[node[i].lchild] = true;
        }else node[i].lchild = -1;
        if(a[1] != '-') {
            node[i].rchild = a[1] - '0';
            Isnodroot[node[i].rchild] = true;
        }else node[i].rchild = -1;
    }
   int root = nodroot();
   postInvert(root);
   bfs(root);
   num = 0;
   inorder(root);
   return 0;
}
大致意思是将一棵二叉树每一个节点的左右子树颠倒之后，输出它的层序遍历序列和中序遍历序列。
输入格式：
二叉树总节点个数 N （二叉树各节点的编号是0 ~ N-1）
各节点的左右子树编号 （若为空，则用 '-'表示）

代码运行出现了段错误，不知道错在哪了！！ 求助

1.txt 中的内容:

8
1 -
- -
0 -
2 7
- -
- -
5 -
4 6

Input Specification:
Each input file contains one test case. For each case, the first line gives a positive integer N (≤10) which is the total number of nodes in the tree -- and hence the nodes are numbered from 0 to N−1. Then N lines follow, each corresponds to a node from 0 to N−1, and gives the indices of the left and right children of the node. If the child does not exist, a - will be put at the position. Any pair of children are separated by a space.

Output Specification:
For each test case, print in the first line the level-order, and then in the second line the in-order traversal sequences of the inverted tree. There must be exactly one space between any adjacent numbers, and no extra space at the end of the line.

Sample Input:
8
1 -
- -
0 -
2 7
- -
- -
5 -
4 6
Sample Output:
3 7 2 6 4 0 5 1
6 5 7 4 3 2 0 1

以上是原题

一直没找到在哪可以回复评论，就把帖子给结了

sorry,没系统学过c++，出现如此低级的错误。
但是我改成 “cin>> a;”之后还是段错误，导致段错误的原因不在这，是吗。

谢谢你