for (n = 0; n < car_num; n++)
    {
        p[n] = rand() % lane;
        //        scanf("第一次检验：%2d", &k);        
        for (i = 0; i < n; i++)
        {
            if (p[n] == p[i])
            {
                m = 0;
                printf("%2d", n);
                scanf("%2", &temp_3);
            }
        }
        if (m == 0)
        {
            n--;
        }
        printf("%2d ,%2d\n", n, p[n]);

    }
// 在主函数里我加了时间为种子，即srand(time(null))

程序还是有点乱，我还是贴上来吧

那是一个检验重复时中断的操作

后面少一个d，程序里没错

car_num是小于lane的，我把程序贴上来

#include<stdio.h>
#include<time.h>
#include<string.h>
#include <stdlib.h>

///////////////////////
#define lane 1000
#define car_num 50
#define time_count 1000
#define pi 0.3
#define vmax 5
#define mg 125000
#define r 0.52
void inicars();
void move();
int FindFront(int);
int v[car_num][lane];
int p[car_num];           //location with p[i];
int a[car_num];           // 加速度
void main()
{    int k;
    srand(time(0));
    inicars();
    for (k = 0; k < time_count; k++)
    {
        move();
        fprintf(h, "时间：%2d\n", k);
    }
    fclose(h);
    printf("OK");
    getchar();
}
void inicars()
{
    int i, j, n, t, temp_1, temp_3;
    int m = 1;
    for (n = 0; n < car_num; n++)
    {
        p[n] = rand() % lane;
        //        scanf("第一次检验：%2d", &k);        
        for (i = 0; i < n; i++)
        {
            if (p[n] == p[i])
            {
                m = 0;
                printf("%2d", n);
                scanf("%2d", &temp_3);
            }
        }
        if (m == 0)
        {
            n--;
        }
        printf("%2d ,%2d\n", n, p[n]);

    }
   

[此贴子已经被作者于2018-9-12 16:55编辑过]

终于贴好了

谢谢，确实可以了，可以解释一下吗，想了一下没有明白