#include <stdio.h>
#include <string.h>
int main(int argc, const char *argv[])
{
    if (argc!=2)
    {
        printf("please input path!\n");
        return -1;
    }
    FILE* fp=fopen(argv[1],"r");
    if (fp == NULL)
    {
        perror("fail to fopen ");
        return -1;
    }
   
    while(1)
    {
        if(fgetc(fp)==EOF)
        {
            if(feof(fp))
                break;
            else
            {
                perror("fail to fgetc");
                return -1;
            }
        }
        fputc(fgetc(fp),stdout);
    }
    if(fclose(fp)==EOF)
    {
        perror("fail to fclose");
        return -1;
    }

    return 0;
}
为什么打印会有缺少

也就是说前面要备份下fgetc咯