[求助]紧急 请问如何获得已经打开的excel文件的文件路径，文件名？
我目前的程序需要获得当前正在打开的所有excel文件的列表，
（所有当前正在打开的excel文件都需要取得，可以用任何方式打开。）
我已经查找了很久，都不能找到C#的方法，
请高手帮忙，多谢！！！
跪求高手帮忙！！！
相关：
这里有一个VB的方法
http://www.bczs.net/xml/2003/4/26/1711527.xml

关于此方法的msn信息在GetObject函数 Visual Basic中。

贴上一段相关代码：
' Add Option Strict Off to the top of your program.
Option Strict Off
' Declare necessary API routines:
Declare Function FindWindow Lib "user32" Alias _
"FindWindowA" (ByVal lpClassName As String, _
ByVal lpWindowName As Long) As Long

Declare Function SendMessage Lib "user32" Alias _
"SendMessageA" (ByVal hWnd As Long, ByVal wMsg As Long, _
ByVal wParam As Long, ByVal lParam As Long) As Long

Sub GetExcel()
Dim MyXL As Object ' Variable to hold reference
' to Microsoft Excel.
Dim ExcelWasNotRunning As Boolean ' Flag for final release.

' Test to see if there is a copy of Microsoft Excel already running.
On Error Resume Next ' Defer error trapping.
' Getobject function called without the first argument returns a
' reference to an instance of the application.
' If the application is not running, an error occurs.
MyXL = GetObject(, "Excel.Application")
If Err().Number <> 0 Then ExcelWasNotRunning = True
Err().Clear() ' Clear Err object in case error occurred.

' Check for Microsoft Excel. If Microsoft Excel is running,
' enter it into the Running Object table.
DetectExcel()

' Set the object variable to reference the file you want to see.
MyXL = GetObject("c:\vb\TEST.XLS")

' Show Microsoft Excel through its Application property. Then
' show the actual window containing the file using the Windows
' collection of the MyXL object reference.
MyXL.Application.Visible = True
MyXL.Parent.Windows(1).Visible = True
' Do manipulations of your file here.
'
End Sub

Sub DetectExcel()
' Procedure dectects a running Excel and registers it.
Const WM_USER = 1024
Dim hWnd As Long
' If Excel is running this API call returns its handle.
hWnd = FindWindow("XLMAIN", 0)
If hWnd = 0 Then ' 0 means Excel not running.
Exit Sub
Else
' Excel is running so use the SendMessage API
' function to enter it in the Running Object Table.
SendMessage(hWnd, WM_USER + 18, 0, 0)
End If
End Sub

[此贴子已经被作者于2006-8-23 11:08:57编辑过]

谢谢楼上的热心人！
不过文件可能不是通过我的程序打开的，比如用户在windows下双击打开，就是说凡是当前系统中打开的excel文件都需要找出来，
而不仅仅是通过执行我程序中的openfiledialog打开的。
谢谢各位帮忙！

[此贴子已经被作者于2006-8-23 11:07:15编辑过]

我曾经试过word有3个线程，当打开一个新文件的时候并不增加新的线程（我也很奇怪）。
excel应该也是这样。
而且我不知道怎么通过线程或进程取得打开的文件名。
通过excel的进程主模块, 只能取得excel.exe的路径，并不能得到被它打开的文件的信息。