键值为157653（8） ,循环位移3
    b = a << (16 - n);
    c = a >> n;

为啥b的值始终不正确，非八进制数3， 而c的值是正确的， 八进制15765

运行结果：
Plese number and cyclic shift length!
157653 3
3375260000 15765
Process returned 16 (0x10)   execution time : 3.520 s
Press any key to continue.

#include<stdio.h>

int main (int argc, char** argv)
{
    int n;
    unsigned a, b, c;
    printf("Plese number and cyclic shift length!\n");
    scanf("%o%d", &a, &n);
    b = a << (16 - n);
    c = a >> n;
    //c = c | b;
    printf("%o %o", b, c);
    return 0;
}

大佬， bin 和 otc 是自己定义的还是有啥含义。你帮我看看反正b移位的结果就是有问题不知道是什么原因
#include<stdio.h>

int main (int argc, char** argv)
{
    int n;
    unsigned a, b, c;
    printf("Plese number and cyclic shift length!\n");
    scanf("%o%d", &a, &n);
    b = a << (16 - n);
    c = a >> n;
    c = c | b;
    printf("%o", b);

}
运行结果：
Plese number and cyclic shift length!
157653
3
3375260000

[此贴子已经被作者于2017-4-26 21:04编辑过]

确实是32位运算改成短整型可行。