#include<stdio.h>
main()
{
        int y,m,d,s,n,leap=0;
        printf("Please input year,month,day:");
        scanf("%d%d%d",&y,&m,&d);
        if((y%4==0&&y%100!=0)||y%400==0)
                leap=1;
        switch(m)
        {
        case 1:s=0;
                if(d>31) printf("data error\n"); break;
        case 2:s=31;
                if(d>29||(d==29&&leap==0)) printf("data error\n"); break;
        case 3:s=59; break;
                if(d>31) printf("data error\n"); break;
        case 4:s=90; break;
                if(d>30) printf("data error\n"); break;
        case 5:s=120; break;
                if(d>31) printf("data error\n"); break;
        case 6:s=151; break;
                if(d>30) printf("data error\n"); break;
        case 7:s=181; break;
                if(d>31) printf("data error\n"); break;
        case 8:s=212; break;
                if(d>31) printf("data error\n"); break;
        case 9:s=243; break;
                if(d>30) printf("data error\n"); break;
        case 10:s=273; break;
                if(d>31) printf("data error\n"); break;
        case 11:s=304; break;
                if(d>30) printf("data error\n"); break;
        case 12:s=334; break;
                if(d>31) printf("data error\n"); break;
        default: printf("data error\n"); break;
        }
        n=s+d;
        if(m>2)
                n=n+leap;
        printf("%d\n",n);
}      
想輸出data error后直接結束整個程序
求解

我寫的break是在if語句的后面 if語句是會執行的

exit(0)  很有用  謝謝你

謝謝你的回復 你沒理解我的意思呢 樓下給出了解答