问题：
1、C 为什么不严格检查参数类型
2、为什么 参数是 int [] 传入 int 是警告，而 double [] 传入 double 是报错
#include <stdio.h>
int a(int []);                                                                                                                                                                                         

int main(void)
{
   int b = 10;
   int s = a(b);

   printf("%d\n", s);
   return 0;
}

int a(int s[])
{
   return s;  
}

// 编译器警告如下
test.c:7:14: warning: incompatible integer to pointer conversion passing 'int' to parameter of type 'int *'; take the address with & [-Wint-conversion]
   int s = a(b);
             ^
             &
test.c:2:11: note: passing argument to parameter here
int a(int []);
          ^
test.c:15:11: warning: incompatible pointer to integer conversion returning 'int *' from a function with result type 'int'; dereference with * [-Wint-conversion]
   return s;
          ^
          *
2 warnings generated.


// 结果输出
10

//----------------
#include <stdio.h>
int a(double []);

int main(void)
{
   double b = 10;
   int s = a(b);

   printf("%d\n", s);
   return 0;
}

int a(double s[])
{                                                                                                                                                                                                           
   return s;
}

// 编译器报错
test.c:7:14: error: passing 'double' to parameter of incompatible type 'double *'; take the address with &
   int s = a(b);
             ^
             &
test.c:2:14: note: passing argument to parameter here
int a(double []);
             ^
test.c:15:11: warning: incompatible pointer to integer conversion returning 'double *' from a function with result type 'int' [-Wint-conversion]
   return s;

不匹配，但是只是警告，没有报错啊，那为什么double 类型报错了呢。是不是参数如果是指针，就只检查他的值是不是整数，毕竟指针的值（即地址）就是整数？

测试如下：
1、 a(int []); int b = 10;
    -- a(b); // 警告
    -- a(&b); // 正常
2、 a(double []); double b = 10;
    -- a(b); // 报错
    -- a(&b); // 正常
是不是在传入当参数为指针的时候，编译器其实只是检查了指针的值（地址）是否为整数呢