#include <stdio.h>
main()
{

      int a = 0, b = 0 , c = 0 ;
      
      printf("请输入a的值: ");
   
      scanf("%d",&a);
   
      printf("请输入b的值: ");
   
      scanf("%d",&b);
   
            {
             if  (a >= 50 , b >= 50)
     
                 c = a * b;
        
                   else if (a >= 50 , b <= 50)
        
                   c = a - b;
               
             else  (a <= 50 , b <= 50)
     
                   c = a + b;
            
   printf("计算结果为: ");
   
   printf("%d\n",c);
            }

      while(1)
      {   
      char c;
      
      printf("请选择继续y或者离开n\n");

      fflush(stdin);
     
      c=getchar();

      if(c=='y')

      continue;
      
      else
      
      break;
      }
      
      return main;
   
}   

上面程序开始就无法运行，这个原程序可以用其他函数执行，那么应该如何用数组   指针运行

这个程序在输入完毕显示后，如何返回到开头继续执行，当然要出现询问是否继续执行，不然会死循环
#include <stdio.h>
main()
{

      int a = 0, b = 0 , c = 0 ;
      
      printf("请输入a的值: ");
   
      scanf("%d",&a);
   
      printf("请输入b的值: ");
   
      scanf("%d",&b);
   
            {
             if  (a >= 50 , b >= 50)
     
                 c = a * b;
        
                    if (a>=50 , b <= 50 )
        
                       c = a - b;
               
                       if (a <= 50 , b <= 50)
                       
                           c = a / b;
                           
                           if(a <= 50 , b >=50)
                           
                             c = a + b;
                    
            
   printf("计算结果为: ");
   
   printf("%d\n",c);
            }
}