这是我刚写的井字游戏，没写注释，如果有意见或问题可以跟贴
由于我用的是linux所以倒数第五行的清空缓冲区的那个函数在windows中不一定可用，注意一下。。。

#include<stdio.h>
#include<ctype.h>
int main(void)
{
    int winner,step,row,column,turn;
    char a[3][3],newgame;
    printf(" 1 | 2 | 3 \n");
    printf("---+---+---\n");
    printf(" 4 | 5 | 6 \n");
    printf("---+---+---\n");
    printf(" 7 | 8 | 9 \n");
    printf("游戏要开始了，先连成三个（横竖斜均可）的人胜利\n"
             "A是X,B是O\n\n");
    while(1){
    char a[3][3]={'1','2','3','4','5','6','7','8','9'};
    turn=0;winner=0;
    do
    {
        turn++;
        printf("It's %c's turn.Please enter a number\n",turn%2?'A':'B');
        scanf("%d",&step);
        step-=1;
        column=step%3;
        row=step/3;
        a[row][column]=turn%2?'X':'O';
        printf(" %c | %c | %c \n",a[0][0],a[0][1],a[0][2]);
        printf("---+---+---\n");
        printf(" %c | %c | %c \n",a[1][0],a[1][1],a[1][2]);
        printf("---+---+---\n");
        printf(" %c | %c | %c \n",a[2][0],a[2][1],a[2][2]);
        if(a[0][0]==a[0][1]&&a[0][0]==a[0][2]) winner=turn%2?1:2;
        else if(a[1][0]==a[1][1]&&a[1][1]==a[1][2]) winner=turn%2?1:2;
        else if(a[2][0]==a[2][1]&&a[2][1]==a[2][2]) winner=turn%2?1:2;
        else if(a[0][0]==a[1][0]&&a[2][0]==a[1][0]) winner=turn%2?1:2;
        else if(a[0][1]==a[1][1]&&a[1][1]==a[2][1]) winner=turn%2?1:2;
        else if(a[0][2]==a[1][2]&&a[1][2]==a[2][2]) winner=turn%2?1:2;
        else if(a[0][0]==a[1][1]&&a[1][1]==a[2][2]) winner=turn%2?1:2;
        else if(a[0][2]==a[1][1]&&a[1][1]==a[2][0]) winner=turn%2?1:2;
        if(turn==9)
            break;
    }
    while(winner==0);
    if(winner!=0)
        printf("winner is %c\n",winner==1?'A':'B');
    else
        printf("和\n");
    printf("wanna another game?\n");
    setbuf(stdin,NULL);
    scanf("%c",&newgame);
    if(tolower(newgame)=='n')
        break;
}}

[此贴子已经被作者于2016-7-21 07:44编辑过]