以下是引用rjsp在2016-6-22 15:23:15的发言：

不怎么想写，因为输入格式和输出格式看起来很烂，需要浪费大量的时间在这些无聊的格式上
#include  
 
void foo( const char* opts, unsigned n, const unsigned elems[] )
{
    unsigned a = 0;
    unsigned b = n;
    unsigned r = 0;
 
    for( ; *opts; ++opts )
    {
        if( *opts == 'R' )
            ++r;
        else if( r%2 == 0 )
            ++a;
        else
            --b;
    }
 
    if( a > b )
        puts( "error" );
    else if( a == b )
        puts( "[]" );
    else if( r%2 == 0 )
    {
        printf( "[%d", elems[a++] );
        for( ; a!=b; ++a )
            printf( ",%u", elems[a] );
        puts( "]" );
    }
    else
    {
        printf( "[%d", elems[--b] );
        for( ; a!=b; --b )
            printf( ",%u", elems1] );
        puts( "]" );
    }
}
 
int main( void )
{
    unsigned count;
    scanf( "%u", &count );
    while( count-- )
    {
        char opts[100001];
        unsigned elems[100001];
        unsigned n;
 
        scanf( "%s", opts );
        scanf( "%u %*c", &n );
        for( unsigned i=0; i!=n; ++i )
            scanf( "%u %*c", elems+i );
 
        foo( opts, n, elems );
    }
 
    return 0;
}
你看，有用的代码就
    for( ; *opts; ++opts )
    {
        if( *opts == 'R' )
            ++r;
        else if( r%2 == 0 )
            ++a;
        else
            --b;
    }
这么一点点，却不得不写大量垃圾代码，所以说这题出得不好

以下是引用rjsp在2016-6-23 08:31:05的发言：

类似的情况，你得告诉别人你输入了什么，否则怎么再现bug？