程序代码：

#include <stdio.h>
#include <stdlib.h>

void k((*pArr[0]).score, int len);

struct Student
{
    int age;
    float score;
    char name[100];
};

int main (void)
{
    int len; 
    struct Student * pArr;
    int i;
    int j;

    k(&pArr[0].score, len);

    printf("请输入学生个数：\n");
    printf("amount=");
    scanf_s("%d", &len);
    pArr = (struct Student *)malloc(len * sizeof(struct Student));

    //输入
    for (i = 0; i < len; i++)
    {
        printf("请输入第%d个学生的信息：\n", i+1);
        printf("age = ");
        scanf_s("%d", &pArr[i].age);

        printf("name = ");
        scanf_s("%s", pArr[i].name, 10); 
        /*
        1.name是数组名，本身就已经是数组首元素的地址，所以pArri[i].name不能写成&pArr[i].name        
        2.由于scanf_s的防溢出机制，所以这个地方要加上字符位数，但此特性只有微软实行，所以可移植性会降低。
            */
        printf("score =");
        scanf_s("%f", &pArr[i].score);
    }

    // 输出
    printf("你输入的信息是：\n\n\n");
    for (i = 0; i < len; ++i)
    {
        printf("第%d个学生的信息是：\n", i + 1);
        printf("age = %d\n", pArr[i].age);
        printf("name = %s\n", pArr[i].name);
        printf("score =%f\n", pArr[i].score);
    }

    return 0;
}

void k((*pArr[0]).score, int len;)
{
    struct Student t;
    int i;

    for (i = 0; i < len - 1; i++)
    {
        if (pArr[i].score > pArr[i - 1].score)
        {
            t = pArr[i];
            pArr[i] = pArr[i - 1];
            pArr[i - 1] = t;
        }
    }
}