public class CatchWho2 {
    public static void main(String[] args) {
        try{
            try {
                throw new ArrayIndexOutOfBoundsException();
            }
            catch(ArithmeticException e) {
                System.out.println(
                  "ArrayIndexOutOfBoundsException" +
                  "/内层 try...catch");
                }
                throw new ArithmeticException();
            }
            catch(ArithmeticException e) {
                System.out.println("发生ArithmeticException");
            }
            catch(ArrayIndexOutOfBoundsException e) {
                System.out.println(
                   "ArrayIndexOutOfBoundsException" +
                   "/外层 try...catch");
                 }
                }
            }
结果显示为：
ArrayIndexOutOfBoundsException/外层 try...catch
为什么没有显示“发生ArithmeticException”

版主能够给我讲解一下吗？我的程序为什么没有显示“发生ArithmeticException”， throw new ArithmeticException();这里扔出的异常不是应该被下面的 catch(ArithmeticException e)所捕捉么？
还有为什么你添加了一个 System.out.println(1/0);就行了呢